Chapter one forum for Civil B

Chapter one forum for Civil B

Number of replies: 2

Please you try to answer the following key question of chapter one 

  1. What is finite precision  
  2. List the source of error
  3. Define error measurements
  4. Define mathematical modeling 
  5. Define Accuracy and precision
  6. change 35.625 in to binary system  

In reply to First post

Re: Chapter one forum for Civil B

by Anteneh Wondmagegn -

Hi Teacher, 

The last question in the quiz no 0.004% has only one significant figure. how can we detect the least from those choices. 

In reply to First post

Re: Chapter one forum for Civil B

by Kasahun Berisha -

1, finite precision: is decimal representation of a number which has been rounded or truncated. There many cases where this may be necessary or appropriate. For example 1/3 and the transcendental numbers e and π all have infinite decimal representations.

2, List the source of error: generally there are two types of error based on their sources.

non-numerical errors  their sources of errors are errors in the mathematical model and input data and numerical errors their sources of errors are truncation errors and round-off errors.

3, Define error measurements:there are two error measurements,

Those are absolute error: is the magnitude of the difference between the true value x and the approximate value xa. The error between two values is defined as abs = kx − xak , where x denotes the exact value and xa denotes the approximation. And

The relative error is defined as rel = kx − xak kxk . which assumes x 6= 0; otherwise relative error is not defined.

4, Define mathematical modeling

  mathematical model:  is a description of a system using mathematical concepts and language. The process of developing a mathematical model is termed mathematical modeling.

5, Define Accuracy and precision

   Accuracy:refers to how closely a value agrees with the true value. 

   precision:refers to how closely values agrees with each other.

6, change 35.625 in to binary system 

35.625 is changed to binary as : first we convert the integer part

(35)10 to ( )2

     35/2  =   17  put here the reminder   1

    17/2  =     8       >>                >>          1

     8/2   =      4       >>               >>           0

     4/2    =      2       >>               >>           0

      2/2    =     1        >>              >>           0

                                                                    1

     collects the reminders up wards  here:(35)10  =(100011)2

Secondly converts the fraction part

   (0.625)10 to ( )2

    0.625*2   = 1.25  put also here the integer part    1

    0.25*2     =0.5     >>                       >>                   0

     0.5*2       =  1      >>                       >>                    1

     collect down ward  (0.625)10   =   (101)2 

    The final result is  (35.625)10  =  (100011.101)2