%%Bisection Method solution illustration  of for loop code
%Dejen ketema marhc,2019
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%f = @(x)(x/2).^2-sin(x);% Example in you handout
%f=@(x)x.^2-2*x+1;
%f=@(x)x.^3-2*x.^2+4*x-3;
%f=@(x)x.^3-2*x.^2-x+2;
%f=@(x)x-2*exp(-x);
f=@(x)x.^2-x-1;
 a = 1;
 b = 2;
 tol=0.001;
 p=bisection_2019_dej(f,a,b,tol);